The parameterization used was

${\displaystyle x=a\left(1-\cos u+\int \limits _{0}^{u}{\frac {\sin ^{2}\alpha }{\sqrt {\sin ^{2}\alpha +\beta }}}d\alpha \right)}$

${\displaystyle y=a(\sin u+{\sqrt {\sin ^{2}u+\beta }})}$

with ${\displaystyle \beta =a^{2}/b^{2}}$ where ${\displaystyle a}$ and ${\displaystyle b}$ are parameters.

This file was created with Python,NumPy and Matplotlib.

from __future__ import division
import matplotlib.pyplot as plt
import numpy as np
from scipy.integrate import quad

plt.rcParams["axes.spines.top"] = False
plt.rcParams["axes.spines.right"] = False


def fun(alpha, beta):
    return np.sin(alpha)**2/np.sqrt(np.sin(alpha)**2 + beta)    
    
a = 1.
b = 0.8
beta = a**2/b**2
u = np.linspace(0, 9*np.pi, 500)
integral = np.array([quad(fun, 0, uval, args=(beta,))
					for uval in u])
x = integral[:, 0]
x = a*(1 - np.cos(u) + x)
y = a*(np.sin(u) + np.sqrt(np.sin(u)**2 + beta))
plt.figure(figsize=(5, 3))
plt.plot(x, y, lw=2)
plt.ylim([0, 3.0])
plt.savefig("Nodary.svg", transparent=True)
plt.show()

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https://creativecommons.org/licenses/by/4.0CC BY 4.0 Creative Commons Attribution 4.0 truetrue